The correct option is B 8.43×1025
From the formula unit of (NH4)2SO4, 4 moles of O-atoms are present in 1 mole of (NH4)2SO4.
Therefore, 8 moles of O−atoms will be present in
=84 moles of (NH4)2SO4
Again, the total number of electrons in one formula unit of (NH4)2SO4
=7×2+8×1+16+8×4=70
So, the total number of electrons in one mole of (NH4)2SO4
=70×6.022×1023
Therefore, the total number of electrons in 84 moles of (NH4)2SO4
=70×6.022×1023×2=8.43×1025