Question

A purse contains four fifty-paise coins, three two-rupee coins and three five-rupee coins. If three coins are selected at random, then what is the probability of getting the minimum amount ?

Answer 1

Total number of coins in the purse = 4+3+3=10

The total number of ways of selecting 3 coins from 10 coins is ${{10}_C}_3=120$.

To get the minimum amount, these three coins must be 50 paise coins. This can be done in ${4_C}_3=4$ ways

Therefore, required probability = $\frac{4}{120}=\frac{1}{30}$.

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