A pythagorean triplet whose two numbers are 8 and 10, then third number is

6

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14

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16

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18

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Solution

The correct option is D $6$
Require pythagorean triplet is (6,8,10) as $6^{2} + 8^{2} = 36 + 64 = 100 = 10^{2}$

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Similar questions

Write a Pythagorean triplet whose smallest number is
(i) 6 (ii) 14 (iii) 16 (iv) 20

6

14

16

16

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