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Question
A quadrilateral ABCD is drawn to circumscribe a circle Such that its sides AB, Bc, CD and AD touchs the circle at P, Q, R , and S respectively. If AB=xcm , BC=7cm, CR=3cm and As=5cm, find x
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Solution
we know that :AB=x
when we draw the figure we get that AB, BC ,CD and AD are tangents to given circle .
So , x=AP+PB .............(i)
AP=AS
BP=BQ
QC=RC=3cm
BQ= 4cm
BQ=BP= 4cm
AP = AS =5cm
From (I) we get that
x= AP+BP
x= 4+5
x=9cm=AB
we know that :AB=x
when we draw the figure we get that AB, BC ,CD and AD are tangents to given circle .
So , x=AP+PB .............(i)
AP=AS
BP=BQ
QC=RC=3cm
BQ= 4cm
BQ=BP= 4cm
AP = AS =5cm
From (I) we get that
x= AP+BP
x= 4+5
x=9cm=AB
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