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Question

A quantity of PCl5 was heated in a 10 litre vessel at 250C
PCl5(g)PCl3(g)+Cl2(g).
At equilibrium, the vessel contains 0.1 mole of PCl5, 0.2 mole of PCl3 and 0.2 mole of Cl2. The equilibrium constant is :

A
0.02
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B
0.05
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C
0.04
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D
0.025
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Solution

The correct option is C 0.04
The equilibrium reaction is PCl5(g)PCl3(g)+Cl2(g).

The expression for the equilibrium constant is Kc=[PCl3][Cl2][PCl5]

Substitute values in the above expression.

Kc=0.210×0.2100.110=0.04.

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