Question

A race car accelerates uniformly from $18.5m/s$ to $46.1m/s$ in $2.47$ seconds. Determine the distance traveled by the car. (in m)

• A. $79.8m$
  
• B. $79m$
  
• C. $7.8m$
  
• D. $9.8m$
  

Answer 1

The correct option is A $79.8m$

Here, initial velocity is $u=18.5m/s$ and final velocity is $v=46.1m/s$

Time taken $t=2.47s$

If $a$ be the acceleration of the car.

Using $v=u+at$,

$46.1=18.5+a\left(2.47\right)$

$⟹$ $a=11.17m/s^2$

If $S$ be the distance traveled by car.

Using formula $v^2-u^2=2aS$,

$(46.1{)}^2-(18.5{)}^2=2\left(11.17\right)S$

$⟹$ $S=79.8m$