Question

A race scooter is seen accelerating uniformly from 18.5m/s to 46.1m/s in 2.47 seconds. Determine the acceleration of the scooter and the distance covered.

Answer 1

Step 1, Given data

Initial velocity $u=18.5m/s$

Final velocity $v=46.1m/s$

Time,$t=2.47sec$

Step 2, Finding the acceleration

We know from the equation of motion

$v=u+at$

Putting all the values

$46.1=18.5+a\times 2.47$

After solving

$a=$11.17 m/$s^2$

Step 3, Finding the distance traveled

We know from the equation of motion

$v^2=u^2+2as$

Putting all the values

${\left(46.1\right)}^2={\left(18.5\right)}^2+2\times 11.17\times s$

After solving

$s=79.81m$

Hence the distance traveled is $79.81m$