Question

A race track is in the form of a ring whose inner and outer circumferences are 44cm and 66cm respectively. Find the width of the track.

• A. 3.50 cm
• B. 1 cm
• C. 3.20 cm
• D. 3cm

Answer 1

The correct option is A 3.50 cm

Width of track $=R_2-R_1$

$=(\frac{C_2}{2\pi }-\frac{C_1}{2\pi })$

$=\frac{1}{2\pi }(66-44)=\frac{7}{2\times 22}\times 22$

$=3.5cm$