A racing car accelerates uniformly from $18.5$ m/s to $46.1$ m/s in $2.47$ seconds. Determine the acceleration of the car and the distance travelled.

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Solution

$a = \frac{(v - u)}{t}$
$= \frac{(46.1 - 18.5)}{2.47}$
$= \frac{27.6}{2.47} = 11.17 \frac{m}{s^{2}}$
The acceleration is $11.17 \frac{m}{s^{2}}$

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A racing car accelerates uniformly from 18.5 m/s to 46.1 m/s in 2.47 seconds. Determine the acceleration of the car and the distance travelled.

a=(v−u)t =(46.1−18.5)2.47 =27.62.47=11.17ms2The acceleration is 11.17ms2

A racing car accelerates uniformly from $18.5$ m/s to $46.1$ m/s in $2.47$ seconds. Determine the acceleration of the car and the distance travelled.

$a = \frac{(v - u)}{t}$
$= \frac{(46.1 - 18.5)}{2.47}$
$= \frac{27.6}{2.47} = 11.17 \frac{m}{s^{2}}$
The acceleration is $11.17 \frac{m}{s^{2}}$