Question

A racing car has a uniform acceleration of $4{\mathrm{ms}}^{-2}$. What distance will it cover in $10\mathrm{s}$ after start?

Answer 1

Step 1: Given

It is given that, the car is initially at rest;

So, the initial velocity $\left(u\right)=0m{s}^{-1}$

Acceleration $\left(a\right)=4m{s}^{-2}$

Time period $\left(t\right)=10s$

Step 2: Applying the second equation of motion for determining the value of distance

As per the second equation of motion, we have, $s=ut+\frac{1}{2}a{t}^2$

Where, s = distance covered

u = initial velocity

a = accleration

t = time

So, we will get,

The total distance covered by the car

$$\begin{gathered} s=0\times 10+\frac{1}{2}\left(4\right)\times {\left(10\right)}^2 \\ \Rightarrow s=0+\frac{1}{2}\times 4\times 100 \\ \Rightarrow s=200m \end{gathered}$$

Therefore, the car will cover a distance of $200meters$ after $10$ seconds.