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Photoelectric Effect

A radiation o...

Question

A radiation of energy $E (E > E_{0})$ falls on a metal whose threshold frequency is $E_{0}$ . The Kinetic energy of the emitted electrons is given by:

A

\frac{E - E_{o}}{2}

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B

E - E_{o}

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C

E_{o} - E

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D

\frac{E}{E_{o}}

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Solution

The correct option is B $E - E_{o}$
If the energy of the incident light is greater than the threshold energy, the excess energy is imparted to the electron as kinetic energy.

$E = E_{o} + K.E.$
$\Rightarrow K.E. = E - E_{o}$

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Photoelectric Effect

Standard XII Chemistry

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