Question

A radioactive element ${}_{92}^{235}X$ is bombarded with a neutron, it generates ${}_{36}^{89}Y$, three neutrons and ${}_{56}^{A}Z.$The value of $A$ is

• A. $140$
• B. $148$
• C. $144$
• D. $142$

Answer 1

The correct option is C $144$

${}_{92}^{235}X{+}_0^{1}n{\to }_{36}^{89}Y{+}_{56}^{A}Z+3{}_0^{1}n$
$A+89+3=236$
$A=144$