Question

When a Uranium isotope is bombarded with a thermal neutron, it generates $\begin{array}{c}141\\ 56\end{array}\text{Ba}$ , three neutrons and

• A. $\begin{array}{c}101\\ 36\end{array}\text{Kr}$
• B. $\begin{array}{c}91\\ 40\end{array}\text{Zr}$
• C. $\begin{array}{c}92\\ 36\end{array}\text{Kr}$
• D. $\begin{array}{c}144\\ 56\end{array}\text{Ba}$

Answer 1

The correct option is C $\begin{array}{c}92\\ 36\end{array}\text{Kr}$

In the given nuclear reaction,

$\begin{array}{c}235\\ 92\end{array}\text{U}+\begin{array}{c}1\\ 0\end{array}n\to \begin{array}{c}141\\ 56\end{array}\text{Ba}+\begin{array}{c}92\\ 36\end{array}\text{Kr}+3\left(\begin{array}{c}1\\ 0\end{array}\text{n}\right)+200\text{MeV}$

From the conservation of nucleons,

$\begin{array}{c}92\\ 36\end{array}\text{Kr}$ will be emitted.