A radioactive element Z A X loses two successive - particles and an - particles such that resulting nuclide is Q P Y- Find the values of P and Q in terms of A and Z-5 MARKS-

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Question

A radioactive element $_{Z}^{A} X$ loses two successive $β - p a r t i c l e s$ and an $α - p a r t i c l e s$ such that resulting nuclide is $_{Q}^{P} Y$ . Find the values of P and Q in terms of A and Z.
[5 MARKS]

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Solution

Reaction: 2 Marks
Symbols: 1 Mark
Representation of P and Q: 2 Marks

The symbolic representation of the reaction is as follows:
$_{Z}^{A} X β - p a r t i c l e - ----- \to M β - p a r t i c l e - ----- \to N {α - p a r t i c l e - ----- \to}_{Q}^{P} Y$
From the above, the symbol of
$M =_{Z + 1}^{A} M a n d N =_{Z + 2}^{A} N$
Since, N nucleus loses one alpha - particle, therefore, the new nucleus has:
mass number = A - 4
Atomic number = Z + 2 - 2 = Z
Hence, P = A - 4 and Q = Z

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A radioactive element AZX loses two successive β−particles and an α−particles such that resulting nuclide is PQY. Find the values of P and Q in terms of A and Z. [5 MARKS]

A radioactive element $_{Z}^{A} X$ loses two successive $β - p a r t i c l e s$ and an $α - p a r t i c l e s$ such that resulting nuclide is $_{Q}^{P} Y$ . Find the values of P and Q in terms of A and Z.
[5 MARKS]