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Question

A radioactive sample decays by 63% of its initial value in 10s. It would have decayed by 50% of its initial value in

A
7s
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B
14s
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C
0.7s
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D
1.4s
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Solution

The correct option is B 7s
Initial amount =x
After time 10 s
Amount =37
Number of half lives to get to 37%
N=log(x0.37x)log(2)=1.4344 half lives.
1.4344 half lives =10 s
1 half life =6.97 s (approximately 7 seconds).
Hence, it would have decayed to 50% in 7 seconds.

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