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Probability Distribution

A random vari...

Question

A random variable X has the following probability distribution
$X = x$ $- 2$ $- 1$ $0$ $1$ $2$ $3$
$P (x)$ $0.1$ $0.1$ $0.2$ $0.2$ $0.3$ $0.1$
Then $E (x) =$

0.8

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0.9

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0.7

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1.1

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Solution

The correct option is A $0.8$
$E (x) = \sum x . P (x)$
$X = x$ $- 2$ $- 1$ $0$ $1$ $2$ $3$
$P (x)$
$0.1$ $0.1$ $0.2$ $0.2$ $0.3$ $0.1$
$x . P (x)$ $- 0.2$ $- 0.1$ $0$ $0.2$ $0.6$ $0.3$
$E (x) = \sum x . P (x) = - 0.2 - 0.1 + 0.2 + 0.6 + 0.3$

Thus $E (x) = 0.8$

Suggest Corrections

Similar questions

X

10 k

$X$	$- 2$	$- 1$	$0$	$1$	$2$	$3$
$P (X)$	$0.1$	$k$	$0.2$	$2 k$	$0.3$	$k$

X :	3	2	1	0	−1
P (X) :	0.3	0.2	0.4	0.1	0.05

X :	0	1	2
P (X) :	0.6	0.4	0.2

X :	0	1	2	3	4
P (X) :	0.1	0.5	0.2	0.1	0.1

X :	0	1	2	3
P (X) :	0.3	0.2	0.4	0.1

X

$X$	$0$	$1$	$2$	$3$	$4$
$P (X)$	$0.1$	$k$	$2 k$	$2 k$	$k$

k

P (X \geq 2)

$X = x$	$- 2$	$- 1$	$0$	$1$	$2$	$3$
$P (X = x)$	$0.1$	$K$	$0.2$	$2 K$	$0.3$	$K$

X

K

X

Values of X :	−2	−1	0	1	2	3
P (X) :	0.1	k	0.2	2k	0.3	k

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