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A ray OA is incident upon a smooth surface POQ. It is reflected back along OB. A normal ON is drawn perpendicular to the surface at O (the point of incidence). The value of AOP is
60. Find the value of the angle of reflection. 


  1. 100

  2. 26

  3. 55

  4. 63


Solution

The correct option is C

55




AOP+AON=90       (as ON is perpendicular to POQ)

AON=9060      (as AOP=60 )
AON=30

Now, AON=angle of incidence = angle of reflection=BON

Thus, angle of reflection =30

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