a ray of light entering water from air (60 degree).the ray bends at the interface of the two media.what is the angle of the refraction of the light ray? air(u1= 1),water(u2=1.33)

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Solution

$a n g l e o f i n c i d e n c e = 60 d e g r e e a n g l e o f r e f r a c t i o n = r r e f r a c t i v e i n d e x o f w a t e r = \frac{\sin i}{\sin r} 1.33 = \frac{\sin 60}{\sin r} \sin r = 0.65 r = \sin^{- 1} (0.65)$

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