A ray of light is incident on a glass-slab from air at an angle . Thickness and refractive index of glass-slab are‘t’ and ‘μa ’ respectively, Find the lateral displacement of the emergent ray respective to incident ray.
1 cm
(1) sin θ = μ sin r
√32 = √3 sin r
r = 30∘
From the figure;
cos r = tAB ⇒ AB = tcosr
sin (θ - r) = d(cosr)t
d = sin(θ−r)cosr (t)
d = 12×√3 (t)
d = 1 cm.