A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster-s angle - If - represents the refractive index of glass with respect to air- then the angle between the reflected and the refracted rays is

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Standard XII

Physics

Polarisation

A ray of ligh...

Question

A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $ϕ$ . If $μ$ represents the refractive index of glass with respect to air, then the angle between the reflected and the refracted rays is

90^{o} + ϕ

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{sin}^{- 1} (μ cos ϕ)

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90^{o}

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90^{o} - {sin}^{- 1} (\frac{sin ϕ}{μ})

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Solution

The correct option is B $90^{o}$
When, the incidence angle of ray is equal to Brewster's angle then angle between reflected & refracted ray is $90^{o}$ (i.e. $π$ /2)

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A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle ϕ. If μ represents the refractive index of glass with respect to air, then the angle between the reflected and the refracted rays is

The correct option is B 90oWhen, the incidence angle of ray is equal to Brewster's angle then angle between reflected & refracted ray is 90o (i.e. π/2)

A ray of light is incident on the surface of a glass plate at an angle of incidence equal to Brewster's angle $ϕ$ . If $μ$ represents the refractive index of glass with respect to air, then the angle between the reflected and the refracted rays is

The correct option is B $90^{o}$
When, the incidence angle of ray is equal to Brewster's angle then angle between reflected & refracted ray is $90^{o}$ (i.e. $π$ /2)