A ray of light strikes a glass slab of thickness t. It emerges on the opposite face, parallel to the incident ray but laterally displaced. The lateral displacement is

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t sin (i - r) cos r

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t \frac{sin i}{cos r}

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t \frac{sin (i - r)}{cos r}

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Solution

The correct option is D $t \frac{sin (i - r)}{cos r}$
the angle of deviation is $i - r$

lateral displacement is $B C (x)$ (from figure)

$x = B C s i n (i - r)$

$B C = \frac{A D}{c o s r}$

$A D = t$ (thickness)

$x = \frac{t s i n (i - r)}{c o s r}$

option $D$ is correct

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A ray of light strikes a glass slab of thickness t. It emerges on the opposite face, parallel to the incident ray but laterally displaced. The lateral displacement is

The correct option is D tsin(i−r)cosrthe angle of deviation is i−rlateral displacement is BC(x)(from figure)x=BCsin(i−r)BC=ADcosrAD=t(thickness)x=tsin(i−r)cosroption D is correct

The correct option is D $t \frac{sin (i - r)}{cos r}$
the angle of deviation is $i - r$

lateral displacement is $B C (x)$ (from figure)

$x = B C s i n (i - r)$

$B C = \frac{A D}{c o s r}$

$A D = t$ (thickness)

$x = \frac{t s i n (i - r)}{c o s r}$

option $D$ is correct