A ray of light traveling in air strikes the water surface at an angle of $40^{o}$ . What will be the refractive index of if angle refraction is $29^{o}$ .

Open in App

Solution

we have,

Refractive index, $n = \frac{sin i}{sin r}$

$= \frac{sin 40}{sin 29}$

$∴ n = 1.32$

Suggest Corrections

Similar questions

Q. A ray of light travelling inside a rectangular glass block of refractive index

\sqrt{2}

is incident on the glass-air surface at an angle o incidence of

45^{o}

.The refractive index of air is one. Under these conditions the ray will

Q. A ray of light travelling in air strikes the surface of glass at angle of

45^{\circ}

. The angle of refraction in the glass will be :

A ray of light travelling in air strikes the glass surface at an angle of incidence $60^{\circ}$ . Find the angle of refraction in glass if refractive index of glass is $\frac{3}{2}$ ? (given $s i n 60^{\circ} = \frac{\sqrt{3}}{2}$ and $s i n 35^{\circ} = \frac{1}{\sqrt{3}}$ )

Q. A ray of light travelling in air strikes a glass slab of

30^{o}

. Calculate the angle of refraction if refractive index of glass is

1.5

Q. A light ray from air strikes an unknown medium at angle 60° as shown. If the angle of refraction is 30°. Evaluate the refractive index of the medium.

Join BYJU'S Learning Program

A ray of light traveling in air strikes the water surface at an angle of 40o. What will be the refractive index of if angle refraction is 29o.

we have,Refractive index, n=sinisinr=sin40sin29∴n=1.32

A ray of light traveling in air strikes the water surface at an angle of $40^{o}$ . What will be the refractive index of if angle refraction is $29^{o}$ .

we have,

Refractive index, $n = \frac{sin i}{sin r}$

$= \frac{sin 40}{sin 29}$

$∴ n = 1.32$