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Standard XII

Chemistry

Zero Order Reaction

A reaction :a...

Question

A reaction :
aA $\to$ product
follows zero order kinetics. The concentration of A with respect to time (t) is given as:

[A_{0}]

[A] - k t

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[A]

[A_{0}] - a k t

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[A]

[A_{0}] + k t

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[A]

[A_{0}] - \frac{k t}{a}

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Solution

The correct option is B $[A]$ = $[A_{0}] - a k t$
$a A \to p r o d u c t$

R = $- \frac{1}{a} \frac{d [A]}{d t} = k (z e r o o r d e r)$
On integrating both sides we get,
$\int_{[A_{0}]}^{[A]} d [A] = - k . a \int_{0}^{t} d t$
On solving above we get,
$[A]$ = $[A_{0}] - a k t$

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A reaction : aA → product follows zero order kinetics. The concentration of A with respect to time (t) is given as:

The correct option is B [A] = [A0]−aktaA→product R = −1ad[A]dt=k (zero order) On integrating both sides we get, ∫[A][A0]d[A] =−k.a∫t0dt On solving above we get, [A] = [A0]−akt

A reaction :
aA $\to$ product
follows zero order kinetics. The concentration of A with respect to time (t) is given as:

The correct option is B $[A]$ = $[A_{0}] - a k t$
$a A \to p r o d u c t$

R = $- \frac{1}{a} \frac{d [A]}{d t} = k (z e r o o r d e r)$
On integrating both sides we get,
$\int_{[A_{0}]}^{[A]} d [A] = - k . a \int_{0}^{t} d t$
On solving above we get,
$[A]$ = $[A_{0}] - a k t$