A reaction at equilibrium involving 2 moles each of PCl5,PCl3, and Cl2 is maintained at 250oC and a total pressure of 3 atm. The value of Kp is : Given: PCl5⇌PCl3+Cl2
A
5
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B
4
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C
8
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D
1
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Solution
The correct option is D 1 PCl5⇌PCl3+Cl2Atequilibrium222 PCl5=26×3,PPCl3=26×3,PCl2=26×3 Kp=pPCl3×pCl2pPCl5=1×11=1