Question

A reaction required three atoms of Mg for two atoms of N. How many grams of N are required for a 3.6 g of Mg?

• A. 2.43
• B. 4.86
• C. 1.4
• D. 4.25

Answer 1

Answer: (C)

1.4

As given, three moles of Mg require two moles of N.
So, $3\times 24$ (molecular mass of Mg) mass of Mg will require $2\times 14$ (molecular mass of N) mass of N.
So, N required for 3.6 g of Mg $=\frac{28}{72}\times 3.6=1.4$ g.