A reactor generates power at a rate of P producing 2 - 1018 fission per second- The energy released per fission is 185 MeV- The value of P is

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Physics

Nuclear Fission

A reactor gen...

Question

A reactor generates power at a rate of $P$ producing $2 \times 10^{18}$ fission per second. The energy released per fission is $185 M e V$ . The value of $P$ is

370 \times 10^{8} M W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.59 M W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

370 M W

No worries! We‘ve got your back. Try BYJU‘S free classes today!

59.2 M W

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $59.2 M W$
Power of fission reactor $=$ Number of fissions per second $\times$ Energy released per fission
$= (2 \times 10^{18}) \times (185 \times 10^{6} \times 1.6 \times 10^{- 19}) W$
$= 59.2 M W$

Suggest Corrections

Similar questions

Q. The energy released per one fission of

U

^{238}

200 M e V

. The number of fissions per second which can produce a power of

1 K W

Q. 200 Mev of energy may be obtained per fission of

U^{235}

. A reactor is generating 1000 KW of power the rate of nuclear fission in the reactor is:

A reactor is generating energy at the rate of $1500 k W$ . How many atoms of $U_{235}$ undergo fission per second, if $180 M e V$ energy is released per fission?

Q. The useful power produced by a reactor of

40

% efficiency , in which

10

^{14}

fissions occuring each second and energy per fission in

275 M e v

, is

Join BYJU'S Learning Program

A reactor generates power at a rate of P producing 2×1018 fission per second. The energy released per fission is 185 MeV. The value of P is

The correct option is D 59.2 MW Power of fission reactor = Number of fissions per second × Energy released per fission =(2×1018) ×(185×106×1.6×10−19)W =59.2 MW

A reactor generates power at a rate of $P$ producing $2 \times 10^{18}$ fission per second. The energy released per fission is $185 M e V$ . The value of $P$ is

The correct option is D $59.2 M W$
Power of fission reactor $=$ Number of fissions per second $\times$ Energy released per fission
$= (2 \times 10^{18}) \times (185 \times 10^{6} \times 1.6 \times 10^{- 19}) W$
$= 59.2 M W$