A reciever has a pressure of 144cm of Hg. After two strokes with an exhaust pump, the pressure is 36cm of Hg. After another two strokes the pressure will be.

9cm of Hg

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

2.4cm of Hg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6cm of Hg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

3cm of Hg

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 9cm of Hg
$P_{n} = P x^{n} F o r t w o s t r o k e s, 36 = 144 x^{2} x^{2} = \frac{1}{4} ∴ x = \frac{1}{2} {P_{n}}^{‵} = 144 x^{4} {P_{n}}^{‵} = 144 {(\frac{1}{2})}^{4} = 9 c m o f H g$

Suggest Corrections

Similar questions

Q. Water flows along a horizontal pipe of non-uniform cross-section. The pressure is

1 cm

H g

where the velocity is

35 cm/s

. At a point where the velocity is

65 cm/s

, the pressure will be

A student performs an experiment using a barometer as shown in the figure below. The atmospheric pressure is given as 76 cm of Hg $(h_{0})$ and the rise in height is 5 cm. What will be the pressure of the gas?

In the experiment given below, if the atmospheric pressure is 76 cm of Hg $(h_{0})$ and the height is 3 cm, find the pressure of the gas in the tube.

Q. A gas is enclosed in a vessel of volume 1000 cc at a pressure of 72.6 cm of Hg. It is being evacuated with the help of a piston pump, which expels 10% gas in each stroke. The pressure after the second stroke will be nearest to

Q. The lengths of air column are 10 cm and 8 cm in a faulty barometer when it reads 72 and 71 cm of Hg. The value of atmospheric pressure is:

Join BYJU'S Learning Program

A reciever has a pressure of 144cm of Hg. After two strokes with an exhaust pump, the pressure is 36cm of Hg. After another two strokes the pressure will be.

The correct option is A 9cm of HgPn=PxnFortwostrokes,36=144x2x2=14∴x=12Pn‵=144x4Pn‵=144(12)4=9cmofHg

The correct option is A 9cm of Hg
$P_{n} = P x^{n} F o r t w o s t r o k e s, 36 = 144 x^{2} x^{2} = \frac{1}{4} ∴ x = \frac{1}{2} {P_{n}}^{‵} = 144 x^{4} {P_{n}}^{‵} = 144 {(\frac{1}{2})}^{4} = 9 c m o f H g$