A rectangle measures $40 c m$ its length and $20 c m$ at its width. Find the ratio of the length to the width??

Open in App

Solution

Length of the rectangle $= 40 c m$
Width of the rectangle $= 20 c m$
$\frac{L e n g t h}{W i d t h} = \frac{40}{20}$
$= \frac{2}{1}$
Therefore, the ratio of the length to the width $=$ $2 : 1$ .

Suggest Corrections

Similar questions

Question 23

Length of a rectangle is three times its breadth. Perimeter of the rectangle is 40 cm. Find its length and width.

A rectangle's length is 5 cm less than twice its width. If the length is decreased by 5 cm and width is increased by 2 cm; the perimeter of the resulting will be 74 cm. Find the length and width of the original rectangle.

The length of a rectangle is twice its width. If its perimeter is 54 cm; find its length.

Q. The area of a rectangle is 540 cm² and its length is 36 cm. Find its width and perimeter.

Q. A rectangle measures

40 c m

at its length and

20 c m

at its width. Find the ratio of the length to the width.

Join BYJU'S Learning Program

A rectangle measures 40cm its length and 20cm at its width. Find the ratio of the length to the width??

Length of the rectangle =40cmWidth of the rectangle =20cmLengthWidth=4020 =21Therefore, the ratio of the length to the width=2:1.

A rectangle measures $40 c m$ its length and $20 c m$ at its width. Find the ratio of the length to the width??

Length of the rectangle $= 40 c m$
Width of the rectangle $= 20 c m$
$\frac{L e n g t h}{W i d t h} = \frac{40}{20}$
$= \frac{2}{1}$
Therefore, the ratio of the length to the width $=$ $2 : 1$ .