wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

A rectangle's length is 5cm less than twice its width. If the length is decreased by 5cm and width is increased by 2cm; the perimeter of the resulting rectangle will be 74cm. Find the length and the width of the original rectangle.

A
15cm and 18cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
25cm and 15cm
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
8cm and 3cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
15cm and 12cm
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 25cm and 15cm
Let width of rectangle be W
length would be L=2W5
If the length is decreased by 5cm, then new L1=2W10cm
and width is increased by 2cm, new width W1=W+2cm
Given, Perimeter =74cm
=>2(2W10+W+2)=74
=>3W8=37
=>3W=45
=>W=15cm
=>L=2W5=2(15)5=25cm

flag
Suggest Corrections
thumbs-up
2
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Distributivity for Algebraic Expressions
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon