A rectangular block of mass $300 k g$ is placed on the ground. Area of contact is $1.5 m^{2}$ . Calculate the pressure exerted by the block. (Take accelaration due to gravity $= 10 m / s^{2}$ ).

500 P a

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1000 P a

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2000 P a

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5000 P a

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Solution

The correct option is C $2000 P a$
Given:
Mass of block, $m = 300 k g$ ,
Area of contact, $A = 1.5 m^{2}$
Acceleration due to gravity, $g = 10 m / s^{2}$

Force acting is equal to weight of the block:
$F = m g$
$F = 300 \times 10 = 3000 N$

From definition of Pressure:
$P = \frac{F}{A}$
$P = \frac{3000 N}{1.5 m^{2}}$
$P = 2000 P a$

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