A rectangular coil of length 10cm and breadth 20cm is placed in uniform magnetic field of induction 20Wbm−2 . A current of 2A is passed through the coil. If it consists of 100 turns, the maximum torque experienced is :
A
40Nm
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B
80Nm
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C
4000Nm
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D
8000Nm
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Solution
The correct option is B80Nm J=niABsinθ maximum at , sinθ=1 ∴J=niAB=100×2×20×10×20×10−4=80Nm