Question

A rectangular coil, of sides 2 cm and 3 cm respectively, has 10 turns in it. It carries of 1 A , and is placed in a uniform magnetic field of 0.2 T in such a manner that its plane makes an angle ${60}^{\circ }$ with the field direction. The torque on the loop is

• A. $6.0\times {10}^{-4}Nm$
• B. $6.0\times {10}^{-6}Nm$
• C. $1.2\times {10}^{-3}Nm$
• D. 6.0 N m

Answer 1

The correct option is D 6.0 N m

$\begin{array}{c}T=NIAB\sin \theta ,\theta =60\\ T=10\times 1\times \left(2\times {10}^{-2}\times 3\times {10}^{-2}\right)\times 0.2\times \frac{\sqrt{3}}{2}\\ 10\times 6\times {10}^{-4}\times \sqrt{3}\times {10}^{-1}\\ 6\sqrt{3}\times {10}^{-4}N-M.\end{array}$