Question

A rectangular iron block of mass 10 Kg is placed on the top of a table the dimensions of the block are 20 CM x 10 cm x 5 cm find the pressure exerted by the blog on the table if the block lies on the table with its side of dimensions first part 20 cm x 10 cm and second part 10 cm x 5 cm

Answer 1

Dear student,
$$\begin{gathered} Case1 \\ Pressure=\frac{Force}{Area}=\frac{10\times 9.8}{20\times 10\times {10}^{-4}}=4900N/m^2 \\ Convertingareafromcmtom(multiplyby{10}^{-4}) \\ Case2 \\ Pressure=\frac{Force}{Area}=\frac{10\times 9.8}{5\times 10\times {10}^{-4}}=19600N/m^2 \end{gathered}$$

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