A rectangular lawn $80 m \times 60 m$ has two roads each $10 m$ wide running in the middle of it, one parallel to the length and the other parallel to the breadth. The cost of graveling them at $R s . 30$ per square meter will be?

38000

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40000

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Rs.

39000

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Rs.

39500

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Solution

The correct option is C Rs. $39000$
Area of road $= 80 (10) + 60 (10) - 10 (10) = 1300 m^{2}$
$∴$ Cost of gravelling them at $R s .30$ per square meter $= 30 (1300) = R s .39000$

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A rectangular lawn 80m×60m has two roads each 10m wide running in the middle of it, one parallel to the length and the other parallel to the breadth. The cost of graveling them at Rs.30 per square meter will be?

The correct option is C Rs. 39000Area of road =80(10)+60(10)−10(10)=1300m2∴ Cost of gravelling them at Rs.30 per square meter =30(1300)=Rs.39000

A rectangular lawn $80 m \times 60 m$ has two roads each $10 m$ wide running in the middle of it, one parallel to the length and the other parallel to the breadth. The cost of graveling them at $R s . 30$ per square meter will be?

The correct option is C Rs. $39000$
Area of road $= 80 (10) + 60 (10) - 10 (10) = 1300 m^{2}$
$∴$ Cost of gravelling them at $R s .30$ per square meter $= 30 (1300) = R s .39000$