A rectangular lawn is 30 m by 20 m. It has two roads each 2 m wide running in the middle of it, one parallel to the length and the other parallel to the breadth. Find the area of the roads.

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Solution

Let ABCD be the rectangular park.
EFGH and IJKL are the two rectangular roads with width 2 m.

Length of the rectangular park AD = 30 cm
Breadth of the rectangular park CD = 20 cm
Area of the road EFGH = 30 m × 2 m = 60 m²
Area of the road IJKL = 20 m × 2 m = 40 m²
Clearly, area of MNOP is common to the two roads.
∴ Area of MNOP = 2 m × 2 m = 4 m²

∴ Area of the roads = Area (EFGH) + Area (IJKL) − Area (MNOP)
= (60 + 40 ) m² − 4 m² = 96 m²

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