Question

A rectangular loop of size (3 cm x 5 cm) having 100 turns carries a current of 2A placed in a uniform magnetic field of 5 T. If the angle between a plane of a coil and magnetic field is ${37}^0$. The torque acting on the loop is (Axis rotation is lying in the plane and perpendicular to B.)

• A. 0.9 Nm
• B. 1.2 Nm
• C. 0.6 Nm
• D. 1.5 Nm

Answer 1

The correct option is B 1.2 Nm

Given :A rectangular loop of size (3 cm x 5 cm) having 100 turns carries a current of 2A placed in a uniform magnetic field of 5 T. The angle between a plane of a coil and magnetic field is ${37}^0$.

Solution :

Formula for the torque on the loop due to magnetic field is BINA $sin\theta$

where B=magnetic field, N= number of turns, I= current, A area of loop

Substituting the values in formula we get

Torque=$5\times 2\times 100\frac{3}{100}\times \frac{5}{100}sin37$

Solving this we get Torque=1.2 Nm

The Correct Opt : B
370