A rectangular park has length $5 m$ and breadth $4 m$ . If four squares are formed along the boundary of it (see figure), what is the perimeter of figure formed?

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Solution

$\begin{matrix} T h e n, P e r i m e t e r o f \Rightarrow f i g u r e = 2 (5 + 5 + 5) + 2 (4 + 4 + 4) P e r i m e t e r = 30 m + 24 m = 54 m \end{matrix}$

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A rectangular park has length 5 m and breadth 4 m. If four squares are formed along the boundary of it (see figure), what is the perimeter of figure formed?

Then,Perimeterof⇒figure=2(5+5+5)+2(4+4+4)Perimeter=30m+24m=54m

A rectangular park has length $5 m$ and breadth $4 m$ . If four squares are formed along the boundary of it (see figure), what is the perimeter of figure formed?

$\begin{matrix} T h e n, P e r i m e t e r o f \Rightarrow f i g u r e = 2 (5 + 5 + 5) + 2 (4 + 4 + 4) P e r i m e t e r = 30 m + 24 m = 54 m \end{matrix}$