A rectangular piece of paper has area $= 24 c m^{2}$ and length $= 5 c m$ . Find its perimeter.

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Solution

Area of rectangele $= l \times b = 24$ cm $²$
Given $l = 5$ cm
so $5 \times b = 24$
or, $b = \frac{24}{5}$
or, $b = 4.8$
Then
perimeter of rectangle=
$= 2 (l + b)$
$= 2 (5 + 4.8)$
$= 2 (9.8)$
$= 19.6$ .

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A rectangular piece of paper has area =24 cm2 and length =5 cm. Find its perimeter.

Area of rectangele =l×b=24 cm²Given l=5 cmso 5×b=24or, b=245or, b=4.8Thenperimeter of rectangle= =2(l+b)=2(5+4.8)=2(9.8)=19.6.

A rectangular piece of paper has area $= 24 c m^{2}$ and length $= 5 c m$ . Find its perimeter.

Area of rectangele $= l \times b = 24$ cm $²$
Given $l = 5$ cm
so $5 \times b = 24$
or, $b = \frac{24}{5}$
or, $b = 4.8$
Then
perimeter of rectangle=
$= 2 (l + b)$
$= 2 (5 + 4.8)$
$= 2 (9.8)$
$= 19.6$ .