A rectangular piece of paper is folded diagonally. If dimensions of the rectangle are $40 c m \times 30 c m$ , what is the length (in cm) of the fold

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Solution

Length of Rectangle $= 40 c m$

Breadth of Rectangle $= 30 c m$

Diagonal of rectangle $= \sqrt{40^{2} + 30^{2}}$

$= \sqrt{1600 + 900}$

$= \sqrt{2500} = 50 c m$

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A rectangular piece of paper is folded diagonally. If dimensions of the rectangle are 40cm×30cm, what is the length (in cm) of the fold

Length of Rectangle =40cmBreadth of Rectangle =30cmDiagonal of rectangle =√402+302 =√1600+900 =√2500=50cm

A rectangular piece of paper is folded diagonally. If dimensions of the rectangle are $40 c m \times 30 c m$ , what is the length (in cm) of the fold

Length of Rectangle $= 40 c m$

Breadth of Rectangle $= 30 c m$

Diagonal of rectangle $= \sqrt{40^{2} + 30^{2}}$

$= \sqrt{1600 + 900}$

$= \sqrt{2500} = 50 c m$