A rectangular room is $6 m$ long, $5 m$ wide and $4 m$ high. Find the total surface area of the four walls.

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Solution

Dimensions of the rectangular room $= 6$ m $\times 5$ m $\times 4$ m
where $l = 6$ m, $b = 5$ m and $h = 4$ m
Total Surface area of the four walls $=$ Lateral surface area of the cuboid
$\Rightarrow$ Total Surface area of the four walls $= 2 (b h + l h)$
$= 2 h (b + l)$
$= 2 \times 4 (5 + 6)$
$= 88$ sq.m
$∴$ Total Surface area of the four walls $= 88$ sq.m

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