A refrigerator whose coefficient of performance is 5, extracts heat from the cooling compartment at the rate of 250J/cycle. Find the amount of heat discharged per cycle to the room.
A
50J
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B
250J
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C
300J
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D
200J
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Solution
The correct option is C300J Coefficient of performance of refrigerator is, β=5;Q2=250J/cycle where Q2 is the heat removed per cycle by the refrigerator. Q1= heat rejected to the source by refrigerator, i.e amount of heat discharged to room. ⇒β=Q2W Or, 5=Q2W ∴W=2505=50J/cycle from energy conservation on refrigerator, Q2+W=Q1 ∴Q1=(250+50)J=300J