A refrigerator works between $4^{0} C$ and $30^{0} C$ . It is required to remove $600$ calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is:
(Take $1 c a l = 4.2 J o u l e s$ )

2.365 W

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23.65 W

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236.5 W

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2365 W

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Solution

The correct option is C $236.5 W$
$β = \frac{Q_{2}}{W} = \frac{T_{2}}{T_{1} - T_{2}}$

$\Rightarrow \frac{600 \times 4.2}{W} = \frac{277}{303 - 277}$

$\Rightarrow W = 236.5 J$

Power, $P = \frac{W}{t} = \frac{236.6}{1} = 236.5 W a t t$

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A refrigerator works between 40C and 300C. It is required to remove 600 calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is: (Take 1cal=4.2 Joules)

The correct option is C 236.5Wβ=Q2W=T2T1−T2⇒600×4.2W=277303−277⇒W=236.5 JPower, P=Wt=236.61=236.5 Watt

A refrigerator works between $4^{0} C$ and $30^{0} C$ . It is required to remove $600$ calories of heat every second in order to keep the temperature of the refrigerated space constant. The power required is:
(Take $1 c a l = 4.2 J o u l e s$ )

The correct option is C $236.5 W$
$β = \frac{Q_{2}}{W} = \frac{T_{2}}{T_{1} - T_{2}}$

$\Rightarrow \frac{600 \times 4.2}{W} = \frac{277}{303 - 277}$

$\Rightarrow W = 236.5 J$

Power, $P = \frac{W}{t} = \frac{236.6}{1} = 236.5 W a t t$