Question

A resistance $R$, an inductance $L$ and a capacitor $C$ are all connected in series with an $AC$ supply. The resistance is of $16\Omega$ and for a given frequency, the inductive reactance of $L$ is $24\Omega$ and capacitance reactance of $C$ is $12\Omega$. If the current in the circuit is $5\text{A}$, find the potential difference across $R,L\text{and}C$ in $\left(\text{V}\right)$.

• A. $120,120,60$
• B. $80,120,60$
• C. $80,80,80$
• D. $60,80,100$

Answer 1

The correct option is B $80,120,60$

The Potential difference across resistance is

$V_R=IR=5\times 16=80\text{V}$

The Potential difference across inductance is

$V_L=I\cdot X_L=I\times \left(\omega L\right)$

$V_L=5\times 24=120\text{V}$

Potential difference across capacitor is

$V_C=I\cdot X_C=I\times \left(\frac{1}{\omega C}\right)$

$V_C=5\times 12=60\text{V}$

Hence, option $\left(B\right)$ is correct.