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Question

# A resistance R, an inductance L and a capacitor C are all connected in series with an AC supply. The resistance is of 16 Ω and for a given frequency, the inductive reactance of L is 24 Ω and capacitance reactance of C is 12 Ω. If the current in the circuit is 5 A, find the potential difference across R, L and C in (V).

A
120, 120, 60
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B
80, 120, 60
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C
80, 80, 80
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D
60, 80, 100
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Solution

## The correct option is B 80, 120, 60The Potential difference across resistance is VR=IR=5×16=80 V The Potential difference across inductance is VL=I⋅XL=I×(ωL) VL=5×24=120 V Potential difference across capacitor is VC=I⋅XC=I×(1ωC) VC=5×12=60 V Hence, option (B) is correct.

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