A resistor of 20 cm length and resistance 5 ohm is stretched to a uniform wire of 40 cm length. The resistance now is-

10 Ω

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5 Ω

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20 Ω

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200 Ω

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Solution

The correct option is C
20 Ω

As R = ρ $\frac{L}{A}$ and volume = L x A = L* πr². = Constant.

By using above equations, we get ratio as 4:1

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