A resistor of resistance $100$ is connected to an AC source c=(12v)sin (250) .Find the power consumed by the bulb:

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Solution

$Q = \frac{V^{2} t}{R}$
$Q = \frac{V^{2} t}{2 R}$
$Q = 12 \times 12 \times 1 \times \frac{10^{- 3}}{2} \times 100$
$Q = 72 \times 10^{- 5} J$

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A resistor of resistance 100 is connected to an AC source c=(12v)sin (250) .Find the power consumed by the bulb:

Q=V2tR Q=V2t2RQ=12×12×1×10−32×100 Q=72×10−5J

A resistor of resistance $100$ is connected to an AC source c=(12v)sin (250) .Find the power consumed by the bulb:

$Q = \frac{V^{2} t}{R}$
$Q = \frac{V^{2} t}{2 R}$
$Q = 12 \times 12 \times 1 \times \frac{10^{- 3}}{2} \times 100$
$Q = 72 \times 10^{- 5} J$