A resistors of 6 - is connected in series with another resistor of 4 - A potential difference of 20 V is applied across the combination-

Given : #160; #160; V = 20 volts #160; #160; #160; #160; #160; R_1 = 6Ω #160; #160; #160; #160; #160; #160; ...

You visited us 27 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Physics

Parallel and Series Combination of Capacitors

A resistors o...

Question

A resistors of $6 Ω$ is connected in series with another resistor of $4 Ω$ . A potential difference of 20 V is applied across the combination.

Open in App

Solution

Given : $V = 20$ volts $R_{1} = 6 Ω$ $R_{2} = 4 Ω$
Total resistance of the circuit $R_{e q} = R_{1} + R_{2} = 6 + 4 = 10 Ω$
$∴$ Current flowing in the circuit $I = \frac{V}{R_{e q}} = \frac{20}{10} = 2$ A

Suggest Corrections

Similar questions

A resistor of $6 Ω$ is connected in series with another resistor of $4 Ω$ . A potential difference of 20 V is applied across the combination. Calculate:

(a) the current in the circuit, and

(b) the potential difference across the $6 Ω$ resistor.

Two resistors of resistance 3 $Ω$ and 6 $Ω$ are in parallel and the combination is in series with a 4 $Ω$ resistor. A potential difference of 90V is applied across the network. The potential difference across 4 $Ω$ the resistor and the current in the 3 $Ω$ resistor are respectively,

Q. A battery of internal resistance,

3 Ω

is connected to

20 Ω

resistor and potential difference across the resistor is 10 V. If another resistor of

30 Ω

is connected in series with the first resistor and battery is again connected to the combination calculate the e.m.f. and terminal potential difference across the combination.

6 Ω

and

12 Ω

resistors are connected in parallel. This combination is connected to series with a

10 V

battery and

6 Ω

resistor. What is the potential difference between the terminals of the

12 Ω

resistors?

Two resistors 4 Ω and 2 Ω are connected in series, and potential difference of 12 V is applied across the combination. Then, the current through the circuit is:

Join BYJU'S Learning Program

A resistors of 6Ω is connected in series with another resistor of 4Ω. A potential difference of 20 V is applied across the combination.

Given : V=20 volts R1=6Ω R2=4ΩTotal resistance of the circuit Req=R1+R2=6+4=10Ω∴ Current flowing in the circuit I=VReq=2010=2 A

A resistors of $6 Ω$ is connected in series with another resistor of $4 Ω$ . A potential difference of 20 V is applied across the combination.

Given : $V = 20$ volts $R_{1} = 6 Ω$ $R_{2} = 4 Ω$
Total resistance of the circuit $R_{e q} = R_{1} + R_{2} = 6 + 4 = 10 Ω$
$∴$ Current flowing in the circuit $I = \frac{V}{R_{e q}} = \frac{20}{10} = 2$ A