Question

A right angled triangle has a hypotenuse, base and the perpendicular side. Let angle $A$ be the angle between the base and the hypotenuse. Draw and find $\sin A$.

Answer 1

Let $PQR$ be a right angle $△,$ right angled at $\theta$ such that,

$\Rightarrow PQ=$ Perpendicular

$\Rightarrow PR=$ Hypotenuse

$\Rightarrow QR=$ Base

$\Rightarrow A=$ angles between base $\left(QR\right)$ $\&$ $\left(PR\right)$ hypotenuse.

$\therefore \sin A=\frac{Perpendicular}{hypotenuse}=\frac{PQ}{PR}$

Hence, the answer is $\frac{PQ}{PR}.$