Question

A right pyramid on a regular hexagonal base is of height $60$ m. Each side of the base is $10$ m. The volume of the pyramid is

• A. $4500{\text{m}}^3$
• B. $5000{\text{m}}^3$
• C. $5196{\text{m}}^3$
• D. $6196{\text{m}}^3$

Answer 1

Answer: (C)

$5196{\text{m}}^3$

Volume of the pyramid
$=\frac{1}{3}\times$ base area $\times$height
$=\frac{1}{3}\times (\frac{3}{2}\sqrt{2}\times {10}^2)\times 60m^2$,
since $\sqrt{3}=1.732$
=$=5196m^3$