A rigid ball strikes with smooth wall as shown in figure. Coefficient of restitution between ball and wall is $⎛ ⎜ ⎜ ⎝ \begin{matrix} tan 37^{\circ} = \frac{3}{4} tan 53^{\circ} = \frac{4}{3} \end{matrix} ⎞ ⎟ ⎟ ⎠$

\frac{3}{4}

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1

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\frac{9}{16}

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\sqrt{\frac{3}{4}}

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Solution

The correct option is C $\frac{9}{16}$

No change in velocity component II to wall as surface is smooth.
$∴ V_{1} sin 37^{\circ} = V_{2} cos 37^{\circ}$
$\frac{3 V_{1}}{5} = \frac{4 V_{2}}{5}$
$\Rightarrow \frac{V_{1}}{V_{2}} = \frac{4}{3}$

Along normal;
$V_{2} sin 37^{\circ} = e V_{1} cos 37^{\circ}$
$e = \frac{V_{2} sin 37^{\circ}}{V_{1} cos 37^{\circ}} = \frac{3}{4} \times \frac{3}{4} = \frac{9}{16}$

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A rigid ball strikes with smooth wall as shown in figure. Coefficient of restitution between ball and wall is ⎛⎜ ⎜⎝tan 37∘=34tan 53∘=43⎞⎟ ⎟⎠

The correct option is C 916 No change in velocity component II to wall as surface is smooth. ∴V1sin 37∘=V2cos 37∘ 3V15=4V25 ⇒V1V2=43 Along normal; V2sin 37∘=eV1cos 37∘ e=V2sin 37∘V1cos 37∘=34×34=916

A rigid ball strikes with smooth wall as shown in figure. Coefficient of restitution between ball and wall is $⎛ ⎜ ⎜ ⎝ \begin{matrix} tan 37^{\circ} = \frac{3}{4} tan 53^{\circ} = \frac{4}{3} \end{matrix} ⎞ ⎟ ⎟ ⎠$